Euler is Probably Involved.
This seems counter-intuitive. Explain how this works, please. \(2^{i\pi} = -1^{ln(2)}\)
Explainer David Marain PRE-CALC
Explain: 2^(iπ) = (-1)^(ln(2))— David Marain (@dmarain) October 7, 2020
Explain: 2^(iπ) = (-1)^(ln(2))
++