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Item 496

0.9999999999999 ... = 1?

Jim Hays et. al. reminded me of this old classic from 8th grade math:

Consider \(\dfrac{9}{10}+\dfrac{9}{100}+\dfrac{9}{1000}+\dfrac{9}{10000}+ ...\),
which can also be written as \(0.\overline{9}\) or \(0.999999 ...\).

Is that less than 1, or equal to 1?


Naturally, you'll need to show them this method:

If N = 0.9999999 ... and 10N = 9.99999 ...
 10N=   9.99999...
 -  N =   0.99999...
--------------------------
  9N = 9
   N = 1


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Source: internet
Jim Hayes, Constance Mueller and several others via email
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