Is That You, Pythagoras?
If we stipulate that
\( (x+12)^2+(y+4)^2+(z+3)^2=0\), then
\( \sqrt{x^2+y^2+z^2}=?\)
Should we brute-force this or is there a more beautiful or subtle way of getting what we want?
(x+12)²+(y+4)²+(z+3)²=0
?(x²+y²+z²)=?
#SATPrep #mathchat #algebra
— David Marain (@dmarain) May 13, 2015
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