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Problems, Questions, and Puzzles to spark discussion and argument in the maths classroom.

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Item 161

Adding Fractions Again

How can we approach this beast of a problem without finding LCM?

\(\dfrac{1}{1} - \dfrac{5}{6} + \dfrac{7}{12} - \dfrac{9}{20} + \dfrac{11}{30} - \dfrac{13}{42} + \dfrac{15}{56} - \dfrac{17}{72} + \dfrac{19}{90} = \dfrac{a}{b}\)


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Number Theory
T.R.Milne
PREALG

Source: T.R.Milne
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