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An interesting Question ... is an algebraic method the only way to do this?
Prove that anywhere on Pascal's triangle, products of numbers in yellow and in orange are equal.
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We started with this:
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We started with this:
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In a factory, the ratio of men to women is 2:3.
The ratio of right-handed men to left-handed men is 7:3
The ratio of right-handed women to left-handed women is 11:1
What fraction of the factory workforce is right-handed?
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It's not included in the PEMDAS Order of Operations ...
Should \(a^{b^c} = ({a^b})^c\) or should it be \(a^{b^c} = a^{(b^c)}\) ??
Does \(3^{2^0}\) equal 1 or 3?
Let's just consider easy numbers {1, 2, 3, 4} so we can explore. What's the probability that the two methods arrive at the same answer?
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Ask your class if there are any Pythagorean anti-Triples: \(\dfrac{1}{a^2} + \dfrac{1}{b^2} = \dfrac{1}{c^2}\) ?
If a, b, c are integers, the question seems harder, since 1/3, 1/4, 1/5 would be (to me) obvious answers - leading to the rules for Pythagorean triples and just using their reciprocals.
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Marilyn Burns pointed out:
Well, does it?
Is there a pattern that always works?
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Take a square number and multiply by four. Is it guaranteed to still be a square number?
Can we generalize this rule?
Can your students explain why?
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The sum of \(\frac{1}{4}\) and a number is equal to the product of \(\frac{1}{4}\) and the number.
(a) Explain why the number must be negative.
(b) What's the number ?
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\( x^2 = 81 \) has two solutions, -9 and 9.
But does \( \sqrt{81} \) have one solution or two?
Is it correct to say that \( \sqrt{81} \) = +9 and -9?
Or should we be saying that \( \sqrt{81} \) is an expression and that \( 9\), \(\frac{18}{2} \), \(27^{2/3} \), and \(1+6+2\), are equivalent expressions?
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